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Re: [Ethereal-users] getting MAC addresses from ethereal
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Ethereal-users: January 2002


> '!(ether[0:2] = 0x0002 and ether[2] = 0x2d) and
> !(ether[0:2] = 0x0050 and ether[2] = 0x8b)' I think.
> But double check my boolean logic; it's
> rusty and it's almost 2:30 AM here :-).

Thanks Marco. I should be able to combine the third
byte with the first two bytes. If so, my capture
expression would look like:
!(ether[6:3] = 0x00022d) and !(ether[6:3]=0x00508b).
Is this right? (I am looking at the source addresses,
so it is at an offset of 6)

Thanks,
rakesh

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